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A uniform cylinder of radius R is spinne...

A uniform cylinder of radius `R` is spinned about it axis to the angular velocity `omega_(0)` and then placed into a corner,. The coeficient of friction between the corner walls and the cylinder is `mu_(k)` How many turns will the cylinder accomplish before it stops?

A

`(1+mu_(k)^(2)omega_(0)^(2)R)/(pi mu_(k)(1+mu_(k))g)`

B

`((1+mu_(k)^(2))omega_(0)^(2)R)/(8pi mu_(k)(1+mu_(k))g)`

C

`(8(1+mu_(k)^(2))omega_(0)^(2)R)/(pi mu_(k)(1+mu_(k))g)`

D

`(3(1+mu_(k)^(2))omega_(0)^(2)R)/(pi mu_(k)(1+mu_(k))g)`

Text Solution

Verified by Experts

The correct Answer is:
B

`theta =(0-omega_(0)^(2))/(-2(2gmu(1-mu))/(R(1+mu^(2)))) =Romega_(0)^(2)(1+mu^(2))/(4gmu(1+mu))`, No. of tunrns `=theta/(2pi) = (R omega^(2)(1+mu^(2)))/(8gmu(1+mu)pi)`
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