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Two particles A,B are moving on two conc...

Two particles A,B are moving on two concentric circles of radii `R_1` and `R_2` with equal angular speed `omega`. At`t=0`,their positions and direction of motion are shown in the figure. The relative velocity `vecV_a-vecV_b` at `t=pi//2omega` is given by :

A

`omega(R_(1)-R_(2))hati`

B

`omega(R_(1) + R_(2))hati`

C

`-omega(R_(1) + R_(2))hati`

D

`omega(R_(2)- R_(1))hati`

Text Solution

Verified by Experts

The correct Answer is:
D

At `t=pi/(2omega), theta = omegat = pi/2`. Hence the position of A and B would
`vecV_(A) = R_(1)omega(-hati)`

`vecV_(B) -V_(A)=(R_(1)omega - R_(2)omega)(-hati)`
or `vecV_(A) - vecV_(B) =(R_(2)-R_(1))omega(hati)`
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