Four solid sphereas each of diameter `sqrt(5) cm` and mass `0.5 kg` are placed with their centres at the corners of a square of side `4 cm`. The moment of inertia of the system about the diagonal of the square is `N xx 10^(-4) kg-m^(2)`, the `N` is -

Explanation

To find the moment of inertia of the system about the diagonal of the square, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Parameters**:
- Diameter of each sphere, \(d = \sqrt{5} \, \text{cm}\)
- Radius of each sphere, \(r = \frac{d}{2} = \frac{\sqrt{5}}{2} \, \text{cm}\)
- Mass of each sphere, \(m = 0.5 \, \text{kg}\)
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