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Consider vec(E)=3xx10^(3) hat(i) (N//C) ...

Consider `vec(E)=3xx10^(3) hat(i) (N//C)` then what is the flux through the square of `10 cm` side, if the normal of its plane makes `60^(@)` angle with the X axis.

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the electric flux through a square area when an electric field is present. The formula for electric flux (Φ) is given by: \[ \Phi = \vec{E} \cdot \vec{A} = E \cdot A \cdot \cos(\theta) \] Where: - \( \Phi \) is the electric flux, ...
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Consider a uniform electric field E = 3xx10^(3) hat(i) N//C . (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane ? (b) What is the flux through the same square if the normal to its plane makes a 60^(@) angle with the x-axis ?

Consider a uniform electric field E = 3xx10^(3) hat(i) N//C . (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane ? (b) What is the flux through the same square if the normal to its plane makes a 60^(@) angle with the x-axis ?

Knowledge Check

  • In the question number 66, the flux through the same square if the line normal to its plane makes a 60^(@) angle with the x-axis is

    A
    `30NC^(-1)m^(2)`
    B
    `10NC^(-1)m^(2)`
    C
    `20NC^(-1)m^(2)`
    D
    `25NC^(-1)m^(2)`
  • Consider a uniform electric field E = 3xx10^(3) hat(i) N//C . (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane ? (b) What is the flux through the same square if the normal to its plane makes a 60^(@) angle with the x-axis ?

    A
    `10 N C^(-1) m^(2)`
    B
    `20 N C^(-1) m^(2)`
    C
    `30 N C^(-1) m^(2)`
    D
    `40 N C^(-1) m^(2)`
  • A uniform electric field E=2xx10^(3)NC^(-1) is acting along the positive x-axis. The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is

    A
    `20NC^(-1)m^(2)`
    B
    `30NC^(-1)m^(2)`
    C
    `10NC^(-1)m^(2)`
    D
    `40NC^(-1)m^(2)`
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