SI unit of permittivity of free space is...

SI unit of permittivity of free space is

Coulomb/Newton-metre

`"Coulomb"^(2)//"Newton-metre"^(2)`

`"Newtonmitre"^(2)//"coulomb"^(2)`

`"Coulomb"^(2)//"(Newton-metre)"^(2)`

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The correct Answer is:

Evaluate from the formula `F=(Q_1Q_2)/(4 pi e_0 r^2)`

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