Charge `2q and -q` are placed at `(a,0) and (-a, 0)` as shown in the figure. The coordinates of the point at which electric field intensity is zero will be `(x,0)` where

Options

A. `-a lt x lt a`
B. `x lt -a`
C. `x gt -a`
D. `0 lt x lt a`

Answer

B

Explanation

For `-a lt x lt a , overlineE_(net)` is along `hat i`, For `x gt a , overline E` can't be zero as field of 2q will be greater
For `x, lt -a , overline (-E)` will be zero where field of 2q and -q cancel out.