The electric field on two sides of a thin sheet of charge is shown in the figure. The charge density on the sheet is

Options

A. `2epsi_(0)`
B. `4 epsi_(0)`
C. `10epsi_(0)`
D. zero

Answer

B

Explanation

let E the external field toward right then on the left side of sheet we have
`E- sigma/(2e_0)=8`……(i)
On the right side of sheet we have
`E=sigma/(2e_0)=12`………(ii)
Solving above equations (i) and (ii) we get `sigma=4e_0`