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If the linear charge density of a cylind...

If the linear charge density of a cylinder is `4 mu C m^(-6)` ,then electric field intensity at point 3.6 cm from axis is :

A

`4 xx 10^(5) NC^(-1)`

B

`2 xx 10^(6) NC^(-1)`

C

`8 xx 10^(7) NC^(-1)`

D

`12 xx 10^(7) NC^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Use `E=lamda/(2 pi e_0 r)` and put values to get `E=2 times 10^6 Ne^-1`
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