Electric field on the axis of a small electric dipole at a distance r is `E_(1) and E_(2)` at a distance of 2r on aa line of perpendicular bisector. Then

Options

A. `vec(E_(2)) = (-vec(E_(1)))/(8)`
B. `vec(E_(2)) = (-vec(E_(1)))/(16)`
C. `vec(E_(2)) = (-vec(E_(1)))/(4)`
D. `E_(2) = - (vec(E_(1)))/(16)`

Answer

B

Explanation

`overline E_1=1/(4 pi e_0) (2 overline p)/r^3` (along `overline p`) , `E_2=-1/(4 pi e_0) overline (p)/(2pi)^3` (Opposite to `overline p`) , So , `overline E_2= overline E_1/16`