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A conductor having a cavity is given a p...

A conductor having a cavity is given a positive charge. Then field strength `E_(A) , E_(B)and E_(C)` at point A( within cavity ), at B ( within conducutor but outside cavity ) and C( near conductor and outside ) respectively will be :

A

`E_(A) = 0 , E_(B) = 0 ,E_(C) = 0 `

B

`E_(A)ne 0 , E_(B) = 0 , E_(C) ne 0`

C

`E_(A)ne0 , E_(B) ne 0,E_(C)ne 0`

D

None of the above

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The correct Answer is:
To solve the problem, let's analyze the electric field strengths at points A, B, and C in relation to the charged conductor with a cavity. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a conductor that has a cavity inside it and is given a positive charge. - Points A, B, and C are defined as follows: - Point A: Inside the cavity. - Point B: Inside the conductor but outside the cavity. - Point C: Outside the conductor. 2. **Electric Field Inside the Cavity (Point A)**: - According to electrostatic principles, the electric field inside a conductor is zero when it is in electrostatic equilibrium. - Since point A is inside the cavity of the conductor, the electric field at point A (EA) is also zero because the charges on the conductor redistribute themselves in such a way that they cancel any electric field within the cavity. - **Result**: \( E_A = 0 \) 3. **Electric Field Inside the Conductor (Point B)**: - For point B, which is inside the conductor but outside the cavity, the electric field is also zero. This is because the electric field inside a conductor in electrostatic equilibrium is always zero. - **Result**: \( E_B = 0 \) 4. **Electric Field Outside the Conductor (Point C)**: - For point C, which is outside the conductor, the positive charge on the conductor creates an electric field. The electric field outside a charged conductor behaves as if all the charge were concentrated at a point at the center of the conductor. - The electric field at point C can be calculated using Coulomb's law: \[ E_C = \frac{kQ}{r^2} \] where \( k \) is Coulomb's constant, \( Q \) is the total charge on the conductor, and \( r \) is the distance from the center of the conductor to point C. - **Result**: \( E_C \neq 0 \) 5. **Final Summary**: - The electric field strengths at points A, B, and C are: - \( E_A = 0 \) - \( E_B = 0 \) - \( E_C \neq 0 \) ### Conclusion: The final answer is: - \( E_A = 0 \) - \( E_B = 0 \) - \( E_C \neq 0 \) Since none of the options provided in the question match this conclusion, the answer is option D: none of the above.

To solve the problem, let's analyze the electric field strengths at points A, B, and C in relation to the charged conductor with a cavity. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a conductor that has a cavity inside it and is given a positive charge. - Points A, B, and C are defined as follows: - Point A: Inside the cavity. ...
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