The electric potential V is given as a function of distance x (metre) by `V = (6x^(2) + 10 x - 9)` volt. Find magnitude of electric field (in V/m) at x= 4.

Explanation

To find the magnitude of the electric field at \( x = 4 \) for the given electric potential function \( V = 6x^2 + 10x - 9 \), we will follow these steps:

### Step 1: Differentiate the Electric Potential Function
The electric field \( E \) is related to the electric potential \( V \) by the equation:
\[ E = -\frac{dV}{dx} \]
First, we need to differentiate the given potential function \( V \) with respect to \( x \).
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