A particle of mass 2 kg and charge 1 mC is projected vertically with a velocity `10ms^(-1)`. There is a uniform horizontal electric field of `10^4NC^(-1)`. Then

Options

A. the horizontal range of the particle is 10 m
B. the time of flight of the particle is 2 s
C. the maximum height reached is 5 m
D. the horizontal range of the particle is 5 m

Answer

A, B, C

Explanation

`T= (2mu_y)/q= (2 times 10)/10=2a, H=u_y^2/(2g) =(10)^2/20=5m, R=1/2 a_x T^2=1/2 ((qE)/m)T^2=10 m`