A, B, C, D, P and Q are points in a uniform electric field. The potentials at these points are `V(A) = 2 V.V (P) = V(B)=B(D)=5V.V (C)=8V`. The electric field at P is

Options

A. `10Vm^(-1)` along PQ
B. `15sqrt2Vm^(-1)` along PA
C. `5Vm^(-1)` along PC
D. `5Vm^(-1)` along PA

Answer

B

Explanation

`V_A=2 vol t`
`V_P=V_B=V_D=5 vol t`.
Since field is uniform
So `E= (Delta V)/(Delta r), vec E x =(2-5)/0.2 =-15 hat I and vec E y=(2-5)/0.2=-15 hat j `
Resultant field `vec E=-15 (hati +hatj)`
`E=15 sqrt2` and direction is along `vec(PA)`