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On moving a charge of 20 coulomb by 2cm,...

On moving a charge of 20 coulomb by 2cm, 2J of work is done, then the potential difference between the points is

A

(a)0.1 V

B

(b)8 V

C

(c)2 V

D

(d)0.5 V

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The correct Answer is:
To find the potential difference between two points when a charge is moved, we can use the formula: \[ V = \frac{W}{q} \] where: - \( V \) is the potential difference, - \( W \) is the work done, - \( q \) is the charge moved. ### Step-by-Step Solution: 1. **Identify the given values:** - Work done \( W = 2 \, \text{J} \) - Charge \( q = 20 \, \text{C} \) 2. **Substitute the values into the formula:** \[ V = \frac{W}{q} = \frac{2 \, \text{J}}{20 \, \text{C}} \] 3. **Calculate the potential difference:** \[ V = \frac{2}{20} = 0.1 \, \text{V} \] 4. **Conclusion:** The potential difference between the two points is \( 0.1 \, \text{V} \).

To find the potential difference between two points when a charge is moved, we can use the formula: \[ V = \frac{W}{q} \] where: - \( V \) is the potential difference, - \( W \) is the work done, - \( q \) is the charge moved. ...
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