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A charge q is placed at the centre of th...

A charge `q` is placed at the centre of the line joining two equal charges `Q`. The system of the three charges will be in equilibrium if `q` is equal to

A

`Q/2`

B

`-Q/2`

C

`Q/4`

D

`-Q/4`

Text Solution

Verified by Experts

The correct Answer is:
D
Let charge q be placed at mid-point of line AB as shown below
Also AB=x [say] `therefore AC=x/2,BC=x/2`
For the system to be in equilibrium, `F_(0q)+F_(Q0)=0 implies 1/(4pi e_0) (Qq)/(x//2)^2 +1/(4 pi e_0) (QO)/x^2=0 or q= -Q/4`
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