A thibn spherical conducting shell of radius R has a charge q. Another charge `Q` is placed at the centr of the shell. The electrostatic potential at a point P a distance R/2 from the centre of the shell is

Options

A. `(2Q)/(4pi epsilon_0R)`
B. `(2Q)/(4pi epsilon_0R)-(2q)/(4pi epsilon_0R)`
C. `(2Q)/(4pi epsilon_0R)+q/(4pi epsilon_0R)`
D. `((q+Q))/(4pi epsilon_0)2/R`

Answer

C

Explanation

Potential at P = Potential due to charge on surface of shell + potential due to charge Q at a distance of `R//2`.
`V_p= (kq)/R+ (kQ)/(R//2)= (kq)/R+ (2kQ)/R=1/(4 pi e_0) (q/E+(2Q)/R)`