Two identical charged spheres suspended from a common point by two massless strings of length `l` are initially a distance `d (d lt lt l)` apart because of their mutual repulsion. The charge begins to leak from both the spheres at a constant rate. As a result the charges approach each other with a velocity `v`. then, as a function of distance x between them

Options

A. `v prop xx^(-1)`
B. `v prop xx^(1//2)`
C. `v prop xx`
D. `v prop xx^(-1//2)`

Answer

D

Explanation

At any instant
`T cos theta - mg`…..(i) ,
`T sin theat=F_e= (kq^2)/x^2`…….(ii)
From Eqs. (i) and (ii) we get , `(kq^2)/x^2= mg tan theta`
`implies q^2=(mg)/k.x/21 x^2 [ because tan theta =x/21] `
`implies q^2= (mg)/(2kl) x^3`…….(iii) `implies 2q (dq)/(dt)=(3mg)/(2kl) x^2 (dx)/(dt)`
`implies 2((mg)/(2kl) x^2)^(1//2) (dq)/(dt) =(3mg)/(2kl) x^2 v [ because q((mg)/(2kl) x^2)^(1//4)] implies vx^(1//2)= constant implies v prop x^(-1//2)`