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For a uniformly charged ring of radius R...

For a uniformly charged ring of radius R, the electric field on its exis has the largest magnitude at a distance h from its centre. Then value of h is :

A

R

B

`R/sqrt2`

C

`R sqrt2`

D

`R/sqrt5`

Text Solution

Verified by Experts

The correct Answer is:
B
`B= (mu_0 IR^2)/(2(R^2+h^2)^(3//2))`
For B to be maximum `(dB)/(dh)=0 implies h= pm R/sqrt2` i.e., option (B)
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