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Charges `-q and +q` located at A and B, respectively, constitute an electric dipole. Distance AB = 2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP = y and `y gt gt 2a`. The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P' such that `OP' = ((y)/(3))`, the force on Q will be close to `((y)/(3) gt gt 2a)`

A

`9F`

B

`27F`

C

`3F`

D

`F/3`

Text Solution

Verified by Experts

The correct Answer is:
B
`F_(eq)=(kpQ)/r^3 implies F_p/F_p' =(r_p/r_p')^3=1/27`
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