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Three charges Q+q and + q are placed at ...

Three charges Q+q and + q are placed at the vertices of a right -angle isosceles triangle as shown below. The net eletrostatic energy of the configuration is zero if the value of Q is :

A

`-2q`

B

`(-sqrt2q)/(sqrt2+1)`

C

`+q`

D

`-q/(1+sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`V=(KQq)/a+(KQq)/(asqrt2) +(Kq^2)/a`
Solving `(kq)/a(Q+Q/sqrt2+q)=0` implies Given `Q=-(qsqrt2)/(sqrt2+1)`
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