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A simple pendulum of length L is placed ...

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by:

A

`2pi sqrt(L/(sqrt(g^2+(q^E/m)^2)))`

B

`2pi sqrt(L/(sqrt(g^2-(q^E/m)^2)))`

C

`2pi sqrt(L/((g-q^E/m)))`

D

`2pi sqrt(L/((g+q^E/m)))`

Text Solution

Verified by Experts

The correct Answer is:
A
`g_(eff)=sqrt(g^(2)+((qE)/(m))^(2))`
`T=2pisqrt((l)/(g_(eff)))`
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