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Three charges Q, +q and + q are placed a...

Three charges Q, +q and + q are placed at the vertices of a right-angled isosceles triangle as shown.
The net electrostatic energy of the configuration is zero if Q is equal to

A

`(-q)/(1+sqrt(2))`

B

`(-2q)/(2+sqrt(2))`

C

`-q`

D

`+q`

Text Solution

Verified by Experts

The correct Answer is:
B
Net electrostatic energy of the configuration will be
`U=K[(q.q)/(a)+(Q.q)/(sqrt(2)a)+(Q.q)/(a)]."Here",K=(1)/(4piepsi_(0))`. Putting U = 0 we get, `Q=(-2q)/(2+sqrt2)`
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