The e.m.f. (`E^(0)` )of the following cells are
`Ag| Ag^(+)(1M) | | Cu^(2+)(1M) | Cu, E^(0) = -0.46V`,`Zn|Zn^(2+)(1M)| | Cu^(2+)(1M) | Cu : E^(0) = +1.10V`
Calculate the e.m.f. of the cell `Zn | Zn^(2+)(1M) | | Ag^(+)(1M) | Ag`

Explanation

To calculate the e.m.f. (E°) of the cell \( \text{Zn} | \text{Zn}^{2+}(1M) || \text{Ag}^{+}(1M) | \text{Ag} \), we will follow these steps:

### Step 1: Identify the half-reactions and their standard reduction potentials.
We have two cells provided:
1. \( \text{Ag} | \text{Ag}^{+}(1M) || \text{Cu}^{2+}(1M) | \text{Cu} \) with \( E° = -0.46 \, \text{V} \)
2. \( \text{Zn} | \text{Zn}^{2+}(1M) || \text{Cu}^{2+}(1M) | \text{Cu} \) with \( E° = +1.10 \, \text{V} \)

From these cells, we can deduce the half-reactions:
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