The standard electrode potentials at 298 K are given below:
`E_(Zn^(2+)| Zn )^(0)` = -0.76 volt and ,`E_(Fe^(2+)|Fe)^(0)` = -0.44 volt ,`E_(H^(2+)|H_(2))^(0)` = -0.0volt `E_(Cu^(2+)| Cu )^(0)` = 0.34 volt
Which of the two electrodes should be combined to form a cell having highest EMF? Identify the cathode and the anode and write the cell reaction. Also mention the direction of flow of electrons in the external as well as the internal circuit.

Explanation

To solve the problem, we need to determine which two electrodes will produce the highest electromotive force (EMF) when combined in a galvanic cell. We will identify the anode and cathode, write the cell reaction, and indicate the direction of electron flow in both the internal and external circuits.

### Step-by-Step Solution:

1. **List the Standard Electrode Potentials**:
- \( E^{\circ}_{Zn^{2+}/Zn} = -0.76 \, \text{V} \)
- \( E^{\circ}_{Fe^{2+}/Fe} = -0.44 \, \text{V} \)
- \( E^{\circ}_{H^{+}/H_2} = 0.00 \, \text{V} \)
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