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I2 and Br2 are added to a solution conta...

I2 and Br2 are added to a solution containing Br– and I– ions. What reaction will occur if,
`I_(2) + 2e^(-) rarr 2I^(-)`, `E^(0) = + 0.54V` and `Br_(2) + 2e^(-) rarr 2Br^(-)`, `E^(0) = +1.09 V?`

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To solve the problem, we need to analyze the given half-reactions and their standard reduction potentials (E° values) to determine which species will be oxidized and which will be reduced. ### Step 1: Identify the half-reactions and their standard reduction potentials We have two half-reactions: 1. \( I_2 + 2e^- \rightarrow 2I^- \) with \( E^\circ = +0.54 \, V \) 2. \( Br_2 + 2e^- \rightarrow 2Br^- \) with \( E^\circ = +1.09 \, V \) ### Step 2: Compare the standard reduction potentials ...
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Br_(2) and I_(2) are added to a solution containing 1M each of Br^(c-) and I^(c-) . What reaction will occur ?

Cl_(2) and Br_(c-) are added to a solution containing 1M each of Cl^(c-) and Br^(c-) . What reaction will occur ?

Given that I_(2)+2e^(-) rarr 2I^(c-)," "E^(c-)=0.54V Br_(2)+2e^(-) rarr 2Br^(-)," "E^(c-)=1.69V Predict which of the following is true.

Write the cell reaction that occurs when the folowing half cells are combined. I_(2)+2e^(-)rarr2I^(-)(1M), E^(@)=+0.54 V Br_(2)+2e^(-)rarrBr^(-)(1M),e^(@)=+1.08 V

Standard reduction potentials of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

Standard reduction potentails of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

In the reaction Bromine 3Br_2 + 6 OH^(-) rarr 5 Br ^(-) + BrO_3^(-) + 3H_2O

Which of the following is the cell reaction that occurs when the following half-cells are combined? I_2 + 2e^(-) to 2I^(-) (1M) , E^@=+0.54 V Br_2+2e^(-) to 2Br (1 M) , E^@=+1.09 V

Standard reduction potentials of the half reactions are given below {:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):} The strongest oxidising and reducing agents respectively are

Given below are a set of half-cell reactions (acidic medium) along with their E_(@) with respect to normal hydrogen electrode values. Using the data obtain the correct explanation to question given below. {:(I_(2)+2e^(-)rarr2I^(-),E^(@)=0.54),(Cl_(2)+2e^(-)rarr2Cl^(-),E^(@)=1.36),(Mn^(2+)+e^(-)rarrMn^(2+),E^(@)=1.50),(Fe^(3+)+e^(-)rarrFe^(2+),E^(@)=0.77),(O_(2)+4H^(+)+4e^(-)rarr2H_(2)O,E^(@)=1.23):} While Fe^(2+) is stable, Mn^(3+) is not stable in acid solution because:

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