One mole of `N_(2)H_(4)` loses ten moles of electrons of form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? (There is no change in the oxidation state of hydrogen.)

Explanation

To find the oxidation state of nitrogen in the new compound Y formed from the loss of electrons by hydrazine (N₂H₄), we can follow these steps:

### Step 1: Write down the initial information
We know that 1 mole of N₂H₄ loses 10 moles of electrons to form a new compound Y. The oxidation state of hydrogen remains unchanged.

### Step 2: Determine the oxidation states in N₂H₄
In hydrazine (N₂H₄), the oxidation state of hydrogen (H) is +1. Since there are 4 hydrogen atoms, their total contribution to the oxidation state is:
\[ 4 \times (+1) = +4 \]
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