The brown ring complex compound is formulated as `[Fe(H_(2)O)_(5)NO]SO_(4)`. The oxidation state of `Fe` is

Explanation

To determine the oxidation state of iron (Fe) in the brown ring complex compound formulated as \([Fe(H_2O)_5NO]SO_4\), we can follow these steps:

### Step 1: Identify the components of the complex
The complex can be simplified to \([Fe(H_2O)_5NO]^{2+}\) because the sulfate ion (\(SO_4^{2-}\)) carries a -2 charge.

### Step 2: Assign oxidation states to known ligands
- Water (\(H_2O\)) is a neutral ligand, so its oxidation state is 0.
- The nitric oxide (\(NO\)) ligand in this context is known to have a +1 oxidation state.
...