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The oxidation number of phosphorus in Ba...

The oxidation number of phosphorus in `Ba(H_2 PO_2)_2` is :

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2 + 2(2 + x - 4) = 0 [`:' Ba(H_(2)PO_(2))_(2)` is neutral molecule]
or 2x - 2 = 0
implies x = +1
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