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How many faradays are required to reduce one mole of `Cr_(2)O_(7)^(-2)to Cr^(+3)` ?

Text Solution

Verified by Experts

The given reaction is `Cr_(2)O_(7)^(2-)+ 14H^(+) + 6e^(-)to2Cr^(3+)+ 7H_(2)O`
one mole `Cr_(2)O_(7)^(2-)` requires 6 mol of electorns for reduction . Hence qunatity of electircity required
`=6molxx96500C mol^(-1) = 5.79xx10^(5)` coulomb
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