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(a)For the reaction : 2AgCl (s) + H(2)...

(a)For the reaction :
`2AgCl (s) + H_(2)(g) ` (1 atm) ` to 2 Ag(s) + 2H^(+) (0.1M) + 2Cl^(-) (0.1M) , DeltaG^(@) = -43600J` at `25^(@)`C.
Calculate the e.m.f. of the cell . [log `10^(-n) = -n`].
(b) Define fuel cell and write its two advantages.

Text Solution

Verified by Experts

`DeltaG^(@) = -nFC_(cell)^(@)`
`E_(cell)^(@)= (DeltaG^(@))/(-nF) = (-43600)/(-2x96500) = 0.226V`
`2AgCl_((s)) + H_(2)(g)(1atm) to 2Ag_((s)) + 2H^(+)(0.1M) + 2Cl^(-) (0.1M)`
`E_(cell) = E_(cell)^(@) -(0.0591)/(n)log([Product])/([Reactant])`
= `0.226 - (0.0591)/(2) ( log (0.1)^4)/(1) =0.226 - (0.0591)/(2) log (10^(-4))= 0.226- (0.0591)/(2) (-4) = 0.226 + 0.1182 = 0.3442V`
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