Which of the following statements are correct concerning redox properties?
(i) A metal M for which `E^(@)` for the half cell reaction `M^(n+)+"ne"^(-)hArrM` is very negative will be a good reducing agent.
(ii) The oxidizing power of the halogen decreases from chlorine to iodine.
(iii) The reducing power of hydrogen halides increases from hydrogen chloride to hydrogen iodide.

Options

A. I,IIand III
B. I and II
C. I only
D. II and III

Explanation

To determine which statements concerning redox properties are correct, we will analyze each statement one by one.

### Statement (i):
**A metal M for which `E^(@)` for the half-cell reaction `M^(n+) + ne^(-) ⇌ M` is very negative will be a good reducing agent.**

**Analysis:**
- The standard reduction potential (`E^(@)`) indicates the tendency of a species to gain electrons (be reduced).
- A very negative `E^(@)` value means that the metal M has a strong tendency to lose electrons (be oxidized), which implies it can effectively reduce other substances.
- Therefore, a metal with a very negative reduction potential is indeed a good reducing agent.

**Conclusion:** This statement is **correct**.

### Statement (ii):
**The oxidizing power of the halogen decreases from chlorine to iodine.**

**Analysis:**
- The oxidizing power of halogens is related to their ability to gain electrons.
- The order of oxidizing power among halogens is Cl₂ > Br₂ > I₂. Chlorine is a stronger oxidizing agent than bromine, which in turn is stronger than iodine.
- This trend is due to the size and electronegativity of the halogens; as the size increases from chlorine to iodine, the ability to attract electrons decreases.

**Conclusion:** This statement is **correct**.

### Statement (iii):
**The reducing power of hydrogen halides increases from hydrogen chloride to hydrogen iodide.**

**Analysis:**
- The reducing power of hydrogen halides (HX) is influenced by the bond strength between H and the halogen.
- As we move from HCl to HI, the bond strength decreases (H-Cl is stronger than H-Br, which is stronger than H-I).
- A weaker bond means that the hydrogen can more easily lose the halogen atom, thus increasing its reducing power.
- Therefore, the reducing power increases from HCl to HI.

**Conclusion:** This statement is **correct**.

### Final Conclusion:
All three statements are correct. Therefore, the answer is that all statements (i), (ii), and (iii) are correct.

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