The metal used to recover copper from a solution of `CuSO_(4)` is :

Options

A. Fe
B. Au
C. Hg
D. Ag

Explanation

To solve the question of which metal can be used to recover copper from a solution of copper sulfate (CuSO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Dissociation of Copper Sulfate:**
- Copper sulfate (CuSO₄) dissociates in an aqueous solution into copper ions (Cu²⁺) and sulfate ions (SO₄²⁻).
- The reaction can be represented as:
\[ \text{CuSO}_4 \rightarrow \text{Cu}^{2+} + \text{SO}_4^{2-} \]

2. **Identify the Reduction Process:**
- To recover copper from the solution, the copper ions (Cu²⁺) need to be reduced to copper metal (Cu).
- The reduction half-reaction can be written as:
\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \]

3. **Determine the Metal to be Used:**
- To facilitate the reduction of copper ions, we need to use another metal (let's call it metal X) that can oxidize and provide the necessary electrons.
- This metal X must be more reactive than copper to effectively displace copper from the solution.

4. **Refer to the Reactivity Series:**
- Metals are arranged in the reactivity series based on their reactivity. A more reactive metal can displace a less reactive metal from its compound.
- In the reactivity series, metals like gold (Au), mercury (Hg), and silver (Ag) are less reactive than copper, while iron (Fe) is more reactive than copper.

5. **Conclusion:**
- Since iron is more reactive than copper, it can be used to recover copper from a copper sulfate solution by displacing it.
- Therefore, the correct answer to the question is:
\[ \text{Iron (Fe)} \]

### Final Answer:
The metal used to recover copper from a solution of CuSO₄ is **Iron (Fe)**.