A lamp draws a current of 1.0 A. Find the charge in coulomb used by the lamp in 60 s :

Options

A. `0.6C`
B. `60C`
C. 600C
D. `0.06C`

Explanation

To solve the question, we need to find the charge in coulombs used by a lamp that draws a current of 1.0 A over a time period of 60 seconds.

### Step-by-Step Solution:

1. **Understand the relationship between current, charge, and time:**
The current (I) is defined as the amount of charge (Q) flowing per unit time (t). The relationship can be expressed by the formula:
\[ I = \frac{Q}{t} \]
Rearranging this formula to solve for charge gives:
\[ Q = I \times t \]

2. **Identify the values given in the problem:**
- Current (I) = 1.0 A (amperes)
- Time (t) = 60 s (seconds)

3. **Substitute the values into the formula:**
Now, we can substitute the values of current and time into the rearranged formula:
\[ Q = 1.0 \, \text{A} \times 60 \, \text{s} \]

4. **Calculate the charge:**
Performing the multiplication:
\[ Q = 1.0 \times 60 = 60 \, \text{C} \]
Therefore, the charge used by the lamp in 60 seconds is 60 coulombs.

5. **Conclusion:**
The charge in coulombs used by the lamp in 60 seconds is 60 C.

### Final Answer:
The charge used by the lamp in 60 seconds is **60 coulombs**.

---