Which substance is obtained in the solution on electrolysis of aqueous `CuSO_4` solution using graphite electrodes?

Options

A. `H_(2)O`
B. `H_(2)SO_(4)`
C. `Na_(2)SO_(4)`
D. `CU(OH)_(2)`

Explanation

To determine the substance obtained in the solution during the electrolysis of aqueous `CuSO4` using graphite electrodes, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrolyte**: The electrolyte in this case is aqueous `CuSO4` (copper(II) sulfate). In solution, it dissociates into `Cu^2+` ions and `SO4^2-` ions.

2. **Identify the Electrodes**: We are using graphite electrodes, which will serve as the cathode (negative electrode) and anode (positive electrode).

3. **Electrolysis Process**: During electrolysis, reduction occurs at the cathode and oxidation occurs at the anode.

4. **Reduction at the Cathode**: At the cathode, the `Cu^2+` ions will undergo reduction. The reaction can be represented as:
\[ Cu^{2+} + 2e^- \rightarrow Cu (s) \]
This means that copper ions gain electrons and are deposited as solid copper on the cathode.

5. **Oxidation at the Anode**: At the anode, water molecules can be oxidized. The reaction can be represented as:
\[ 2H_2O \rightarrow O_2 (g) + 4H^+ + 4e^- \]
This indicates that oxygen gas is released at the anode, along with hydrogen ions.

6. **Remaining Ions in Solution**: After the electrolysis, the remaining ions in the solution will be `H^+` ions and `SO4^2-` ions. These ions can combine to form sulfuric acid:
\[ 2H^+ + SO4^{2-} \rightarrow H_2SO4 \]

7. **Final Conclusion**: The substance obtained in the solution after the electrolysis of aqueous `CuSO4` using graphite electrodes is sulfuric acid (`H2SO4`).

### Final Answer:
The substance obtained in the solution is **sulfuric acid (H2SO4)**.

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