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The molar conductivities of wedge(NaOAc...

The molar conductivities of `wedge_(NaOAc)^(@)` and `wedge_(HCl)^(@)` at infinite dilution in water at `25^(@)C`are 91.0 and 426.2 S `cm^(2)//mol` respectively. To calculate `wedge_(HOAc)^(@)`, the additional value required is :

A

`wedge_(H_(2)O)^(@)`

B

`wedge_(KC1)^(@)`

C

`wedge_(NaoH)^(@)`

D

`wedge_(NaC1)^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`wedge_(CH_(3)COOH)^(@) = wedge _(CH_(3)COONa)^(@)+ wedge_HCl^(@) - wedge_(Nacl^(@)`
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