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What will be the reduction potential of ...

What will be the reduction potential of a hydrogen electrode which is filled with HCl solution of pH value 1.0? (at 298 Kelvin)

A

`(-59.15V)`

B

`(+59.15)`

C

`(+59.15mV)`

D

`(-59.15mV)`

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The correct Answer is:
To determine the reduction potential of a hydrogen electrode filled with an HCl solution of pH 1.0 at 298 K, we can follow these steps: ### Step 1: Understand the Reaction The reduction reaction for the hydrogen electrode can be represented as: \[ \text{2H}^+ + 2e^- \rightarrow \text{H}_2(g) \] This indicates that two protons (H⁺ ions) gain two electrons to form hydrogen gas. ### Step 2: Use the Nernst Equation The Nernst equation relates the reduction potential (E) to the standard reduction potential (E°) and the concentrations of the reactants and products: \[ E = E^\circ - \frac{0.05915}{n} \log Q \] Where: - \( E \) = reduction potential - \( E^\circ \) = standard reduction potential (0 V for the hydrogen electrode) - \( n \) = number of moles of electrons transferred (2 for this reaction) - \( Q \) = reaction quotient ### Step 3: Determine the Concentration of H⁺ Given that the pH of the solution is 1.0, we can find the concentration of H⁺ ions: \[ \text{pH} = -\log[\text{H}^+] \] \[ [\text{H}^+] = 10^{-\text{pH}} = 10^{-1} = 0.1 \, \text{M} \] ### Step 4: Calculate the Reaction Quotient (Q) For the hydrogen electrode, the reaction quotient \( Q \) is given by: \[ Q = \frac{1}{[\text{H}^+]^2} \] Substituting the concentration of H⁺: \[ Q = \frac{1}{(0.1)^2} = \frac{1}{0.01} = 100 \] ### Step 5: Substitute Values into the Nernst Equation Now we can substitute the values into the Nernst equation: \[ E = 0 - \frac{0.05915}{2} \log(100) \] Since \( \log(100) = 2 \): \[ E = -\frac{0.05915}{2} \times 2 \] \[ E = -0.05915 \, \text{V} \] ### Step 6: Convert to Millivolts To express the potential in millivolts: \[ E = -0.05915 \, \text{V} \times 1000 \, \text{mV/V} = -59.15 \, \text{mV} \] ### Final Answer The reduction potential of the hydrogen electrode filled with HCl solution of pH 1.0 at 298 K is: \[ \boxed{-59.15 \, \text{mV}} \] ---

To determine the reduction potential of a hydrogen electrode filled with an HCl solution of pH 1.0 at 298 K, we can follow these steps: ### Step 1: Understand the Reaction The reduction reaction for the hydrogen electrode can be represented as: \[ \text{2H}^+ + 2e^- \rightarrow \text{H}_2(g) \] This indicates that two protons (H⁺ ions) gain two electrons to form hydrogen gas. ### Step 2: Use the Nernst Equation ...
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