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The standard reduction potentials at 298...

The standard reduction potentials at 298K for the following half cells are given :
`ZN^(2+)(aq)+ 2e^(-)Zn(s)`, `E^(@) = - 0.762V`
`Cr^(3+)(aq)+ 3e^(-) Cr(s)`, `E^(@) = - 0.740V`
`2H^(+) (aq)+2e^(-) H_(2)(g)`, `E^(@)= 0.000V`
`Fe^(3+)(aq)+ e^(-) Fe^(2+)(aq)`, `E^(@) = 0.770V`
which is the strongest reducing agent ?

A

`Zn((s))`

B

`Cr((s))`

C

`H_(2)((g))`

D

`Fe^(2+((aq))`

Text Solution

AI Generated Solution

To determine which is the strongest reducing agent among the given half-cells, we need to analyze the standard reduction potentials provided. The reducing agent is the species that gets oxidized (loses electrons) while reducing another species (gaining electrons). ### Step-by-Step Solution: 1. **Understand Reduction Potentials**: - The standard reduction potential (E°) indicates the tendency of a species to gain electrons (be reduced). A more negative E° value means a weaker tendency to be reduced, and thus a stronger tendency to be oxidized. 2. **List the Given Half-Cells and Their Potentials**: ...
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Knowledge Check

  • Calculate the reduction potential for the following half cell reaction at 298 K. Ag^(+)(aq)+e^(-)toAg(s) "Given that" [Ag^(+)]=0.1 M and E^(@)=+0.80 V

    A
    0.741 V
    B
    0.80 V
    C
    `-0.80`V
    D
    `-0.741`V

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