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Consider the cell : Zn|Zn^(2+)(aq)(1.0...

Consider the cell `:`
`Zn|Zn^(2+)(aq)(1.0M)||Cu^(2+)(aq)(1.0M)||Cu`
Thee standard reduction potentials are `0.350V` for
`Cu^(2+)(aq)+2e^(-)rarrCu ` and `-0.763V` for
`Zn^(2+)(aq)+2e^(-) rarr Zn`
`a.` Write the cell reaction.
`b.` Calculate the `EMF` of the cell.
`c.` Is the reaction spontaneous or not ?

Text Solution

Verified by Experts

(i) The cell reaction is `Zn+Cu^(2+) to Zn^(2+)+Cu`
(ii) `E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)=0.350-(-0.763)=1.113V`
Q both `Zn^(2+)` and `Cu^(2+)` are unit concentration,`E=E^(@)=1.113V`
(iii Q `E_(cell)=1.1113lt0`
`DeltaG-=-nEF lt0`
Therefore, the cell reaction is sponteneous.
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