Home
Class 12
CHEMISTRY
Faraday's laws of electrolysis are relat...

Faraday's laws of electrolysis are related to :

A

atomic number of the cation

B

atomic number of the anion

C

equivalent weight of the electrolyte

D

speed of the cation

Text Solution

Verified by Experts

`W_1/W_2=E_1/E_2=(Z_1it)/(Z_2it) therefore Z_1/Z_2=E_1/E_2`
there `E_1` and `E_2` are equivalent weights of the ions.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    VMC MODULES ENGLISH|Exercise FUNDAMENTAL|50 Videos

  • ELECTROCHEMISTRY

    VMC MODULES ENGLISH|Exercise ENABLE|50 Videos

  • ELECTROCHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|57 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE)|30 Videos

  • ENVIRONMENTAL CHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|39 Videos

Similar Questions

Explore conceptually related problems

State Faraday's laws of electrolysis. How would you determine the equivalent mass of a substance with the help of these laws ?

Use of electrolysis is .

By virtue of Faraday's second law of electrolysis, the electrochemical equivalent of the two metals liberated at the electrodes has the same ratio as that of their

Faraday law of electrolysis indirectly shows

Mention the Faraday's laws of electrolysis.

How will show that Faraday's second law of electrolysis is simply corollary of the first law.

State Faraday's second law of electrolysis. How is the law helpful in determining the equivalent weight of a substance ?

According to the Faraday Law of electrolysis, the mass deposited at electrode proportional to:

State Faraday's first law of electrolysis . How much charge in terms of Faraday is required for the reduction of 1mol of Cu^(2+) to Cu. (b) Calculate emf of the following cell at 298 K : Mg(s) | Mg ^(2+)(0.1 M)||Cu^(2+) (0.01)|Cu(s) [Given E_(cell)^(@)=+ 2.71V, 1 F = 96500C mol^(-1)]

State Faraday's first law of electrolysis.

VMC MODULES ENGLISH-ELECTROCHEMISTRY-JEE Advanced (Archive)
  1. Given reasons in one or two sentences. “Anhydrous HCl is a bad conduc...

    Text Solution

    |

  2. Consider the cell : Zn|Zn^(2+)(aq)(1.0M)||Cu^(2+)(aq)(1.0M)||Cu Th...

    Text Solution

    |

  3. Faraday's laws of electrolysis are related to :

    Text Solution

    |

  4. The electric charge for electrode deposition of one gram equivalent of...

    Text Solution

    |

  5. A solution containing 1 mol per litre of each Cu(NO(3))(2), AgNO(3), ...

    Text Solution

    |

  6. The reaction 1//2H2(g)+AgCl(s) rarr H^(o+)(aq)+Cl^(c-)(aq)+Ag(s) oc...

    Text Solution

    |

  7. How long a current of 3A has to be passed through a solution of silver...

    Text Solution

    |

  8. The EMF of a cell corresponding to the reaction : Zn((s)) + 2H((aq))^(...

    Text Solution

    |

  9. During the discharge of a lead storage battery, the density of sulphur...

    Text Solution

    |

  10. A 100 watt, 110 volt incandescent lamp is connected in series with an ...

    Text Solution

    |

  11. In a fuel cell, hydrogen and oxygen react to produce electricity. In p...

    Text Solution

    |

  12. A cell contains two hydrogen electrodes. The negative electrode is in ...

    Text Solution

    |

  13. The standard reduction potential at 25^(@)C of the reaction 2H(2)O+2...

    Text Solution

    |

  14. An acidic solution of Cu^(2+) salt containing 0.4g of Cu^(2+) is elect...

    Text Solution

    |

  15. The standard reduction potential of Cu^(2+)|Cu and Ag^(o+)|Ag electrod...

    Text Solution

    |

  16. Calculate the quantity of electricity that would be required to reduce...

    Text Solution

    |

  17. A current of 1.70 A is passed through 300.0 mL of 0.160 M solution of ...

    Text Solution

    |

  18. Zinc granules are added in excess to 500mL OF 1.0m nickel nitrate solu...

    Text Solution

    |

  19. For the galvanic cell: Ag|AgCI(s)|KCI(0.2M)||KBr(0.001M)|AgBr(s)|Ag, c...

    Text Solution

    |

  20. An aqueous solution of NaCl on electrolysis gives H(2)(g), Cl(2)(g), a...

    Text Solution

    |