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The EMF of a cell corresponding to the r...

The EMF of a cell corresponding to the reaction : `Zn_((s)) + 2H_((aq))^(+) toZn^(2+) (0.1 M) + H_(2(g)) ` ( 1 atm ) is 0.28 volt at `15^@C`.
The pH of the solution at the hydrogen electrode is (Given : `E_(Zn^(2+)//Zn)^@`=-0.76 volt , `E_(H^+ // H_2)^@`= 0 volt )

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A anode: `Znto Zn^(2+)+2e^(-) E^(@)=0.76 V`
At cathode :`2H^(+)+2e^(-) to H_2(g) E^(@)=0.00 V`
`implies "For" Zn+2H^(+)to Zn^(2+)+H_2(g) E^(@)=0.76V`
`E=E^(@)-0.0592/2log. ((Zn^(2+)))/((H^(+))^(2)) implies (2(E-E^(@)))/0.0592=-log [log[Zn^(2+)]-2log1/([H^(+)]`
`implies -16.2 =-log (0.1) -3pH =(1+16.2)/2=8.6`
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