A current of 1.70 A is passed through 300.0 mL of 0.160 M solution of a `ZnSO_(4)` for 30 s with a current efficiency of 90% . Find out the molarity of `Zn^(2+)` after the deposition Zn. Assume the volume of the solution to remain cosntant during the electrolysis.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the quantity of electricity (Q)

The quantity of electricity (Q) can be calculated using the formula:
\[ Q = I \times t \]
Where:
- \( I \) = current in amperes (1.70 A)
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