`2Ag^(+) + C_(6)H_(12) O_(6) + H_(2)O rightarrow 2Ag(s) + C6H_(12)O_(7) + 2H^(+)` Find ln K of this reaction.

Options

A. `66.13`
B. `58.38`
C. `28.30`
D. `46.29`

Explanation

To find the natural logarithm of the equilibrium constant (ln K) for the given electrochemical reaction, we can follow these steps:

### Step 1: Identify the half-reactions and their standard electrode potentials.
The reaction is:
\[ 2Ag^+ + C_6H_{12}O_6 + H_2O \rightarrow 2Ag(s) + C_6H_{12}O_7 + 2H^+ \]

1. **Reduction half-reaction**:
\[ Ag^+ + e^- \rightarrow Ag \]
...