Electrolysis of dilute aqueous NaCl solution was carried out by passing 10A current. The timerequired (in seconds ) to liberate 0.01 moles of `H_(2)` gas at the cathode is `: [ 1F =96500C ]`

Options

A. `9.65 xx10^(4)s`
B. `19.3xx10^(4)S`
C. `28.95xx10^(4)S`
D. `38.6xx10^(4)s`

Explanation

`Q=ixxt ,Q=10xx10^(-3)xxt`
`2H_2O+2e^(-) to H_2+2O H^(-)`
To liberate 0.01 mole of `H_2` ,0.02 Faraday charge is required.
`therefore Q=0.02xx96500=10^(-2)xxt , t=19.30xx30^(4) sec`