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Consider the following cell reaction 2...

Consider the following cell reaction
`2Fe_((s))+O_(2(g))+4H_((aq.))^(o+)rarr2Fe_((aq.))^(+2)+2H_(2)O_((l))" "E^(@)=1.67V`
At `[Fe^(+2)]=10^(-3)M, P(O_(2))=0.1" atm and pH = 3, the cell potential at "25^(@)C` is …….
Use `(2.303RT)/(F)=0.059`

A

`(1.47V)`

B

`(1.77V)`

C

`(1.87V)`

D

`(1.57V)`

Text Solution

Verified by Experts

`2Fe_((s))+O_(2_((g))+4H_((aq))^(+))to 2Fe_((aq))^(+2)+2H_2O_((l))`
n=4 (no. of electrons involved)
`E_(cell)=E_(cell)^(o)-(0.0591)/nlog. ([Fe^(2+)])/(P_(o_2)xx[H^(+)]^(4))=1.67-(0.0591)/4log.((10^(-3))^(2))/(0.1xx(10^(-3))^(4)){Q [H^(+)]=10^(-pH)}`
`1.67-0.103=1.57V`
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