For the following cell, `Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)|Cu(s)` when the concentration of `Zn^(2+)` is 10 times the concentration of `Cu^(2+),` the expression for `DeltaG("in J mol"^(-1))` is [F is Faraday constant, R is gas constant, T is temperature, `E^(@)"(cell)"=1.1V`]

Options

A. (2.30RT-2.2F)
B. (-2.2F)
C. (2.30RT+ 1.1F)`
D. 1.1F

Explanation

Given cell is `Zn_((s))|ZnSO_(4_((aq)))PCuSO_(4_((aq)))|Cu_((s)), E_(cell)^(@)=1.1V`
The cell is given reaction is
`Zn+Cu^(2+)toZn^(2+)+Cu`
`E_(vell)=E_(cell)^(@)-(2.30RT)/(nF)log .([Zn^(2+)])/([Cu^(2+)])`
On subsituting values ,we get,
`E_(cell)=1/1-(2.30RT)/(2F)log.(10[Cu^(2+)])/([Cu^(2+)])=1.1-(2.303RT)/(2F) Q log 10=1]`
`DeltaG=-nFE_(cell)`
On subsituting values, we get :
`DeltaG=-2F(1.1-(2.303RT)/(2F))=-2.2F +2.303RT-2.2F`