The conductance of 0.0015 M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 120 cm with an area of cross-section of `1 cm^(2)`. The conductance of this solution was found to be `5xx10^(-7) S`. The pH of the solution is 4. Calculate the value of limiting molar conductivity.

Explanation

To solve the problem step by step, we will calculate the limiting molar conductivity of the weak monobasic acid solution based on the given data.

### Step 1: Calculate the conductivity (κ) of the solution

The relationship between conductance (G), conductivity (κ), area (A), and distance (L) is given by the formula:

\[
G = \kappa \cdot \frac{A}{L}
...