A detergent `C_2H_2` solution becomes a colloidal sol at a concentration of `10^3 M` On an average`10^33` colloidal particles are present in `1mn^3` What is the average number of ion are contain in one colloidal particle (micelle)? [Given `NA=6 diamond ^2` ]

Options

A. `6 diamond O^3`
B. 10
C. 60
D. None of the above

Explanation

To solve the problem step by step, we will follow these instructions:

### Step 1: Understand the given data
We have a detergent solution that becomes a colloidal sol at a concentration of \(10^3 \, \text{M}\). The average number of colloidal particles in \(1 \, \text{mm}^3\) is \(10^{13}\). We need to find the average number of ions contained in one colloidal particle (micelle).

### Step 2: Convert the concentration from molarity to total number of particles
1. **Convert \(1 \, \text{L}\) to \(1 \, \text{mm}^3\)**:
- \(1 \, \text{L} = 1000 \, \text{mL} = 10^6 \, \text{mm}^3\)
...