AT STP the volume of nitrogen gas required to cover a sample of silica gel, assuming Langmuir monolayer adsorption, is found to be `1.3^30^1` of the gel. The area occupied by a nitrogen molecule is `0.1 0^2` What is the surface area per gram of silica gel? [Given `N_A =6 diamond ^2`]

Options

A. `5.5^2 6^1`
B. `3.4^2 8^1`
C. `1.6^2 1^7`
D. None of these

Explanation

To solve the problem, we need to calculate the surface area per gram of silica gel based on the given data. Here’s a step-by-step breakdown of the solution:

### Step 1: Convert the volume of nitrogen gas to cubic centimeters
The volume of nitrogen gas required to cover the silica gel is given as \( 1.3 \times 10^{30} \) cm³.

**Hint:** Remember that 1 liter = 1000 cm³, and at STP, 1 mole of gas occupies 22.4 liters or 22400 cm³.

### Step 2: Calculate the number of nitrogen molecules in the given volume
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