Home
Class 12
CHEMISTRY
In an adsorption experiment, a graph bet...

In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log `(x/m)` axis was found to be `0.3010` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `0.5` atm` .

Text Solution

Verified by Experts

According to the freundich equation
`x/m=KP^(1/n) or log times 1/(mn) log l`
/ Plot of `log ""x/m` versus log is linear with slope `1/n` and intercept log
Thus, `1/n tan^-1 , log L or K ar`
At PO. x/m+1=PO`
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|14 Videos

  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE MAIN ARCHIVE|25 Videos

  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise LEVEL-1|74 Videos

  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|7 Videos

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise EXERCISE-J|10 Videos

Similar Questions

Explore conceptually related problems

In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45^(@) . The intercept on the log y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.

In an adsorption experiment a graph between log x/m versus log P was fond to be linear with a slope of 45^@) . The intercept on the log x/m axis was found to 0.70 . Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 1 atm [log5=0.70]

In an Adsorption experiment a graph between log x/m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x/m was found to be 0.3010. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 0.6 bar.

In an adsorption experiment, a graph of log(x/m) versus log P was found to be linear with a slope of 45°, and the the intercept is found to be 0.3010. The amount of gas adsorbed per gram charcoal under a pressure of 0.8 atm is

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

When a graph is plotted between log x/m and log p, it is straight line with an angle 45^@ and intercept 0.6020 on y-axis.if initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gram of adsorbent :

For the adsorption of a gas on a solid, the plot of log(x/m) versus log P is linear with slope equal to:

Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

For the adsorption of a gas on a solid, the plot of log(x/m) versus log p is linear with slope equal to

Graph between log((x)/(m)) and log P is straight line at angle of 45^(@) with the intercept of 0.6020. The extent of adsorption ((x)/(m)) at a pressure of 1 atm is

VMC MODULES ENGLISH-SURFACE CHEMISTRY-LEVEL-2
  1. TEL minimizes the Knocking effect when mixed with petrol. It acts as :...

    Text Solution

    |

  2. Although, nitrogen does not adsorb on a surface at room temperature, i...

    Text Solution

    |

  3. Which of the following gas molecules have minimum value of enthalpy of...

    Text Solution

    |

  4. In Langumir's model of adosrption of a gas on a solid surface :

    Text Solution

    |

  5. Which of the followings is not correct about colloids?

    Text Solution

    |

  6. From the given following sol how many can coagulate the haemoglobin so...

    Text Solution

    |

  7. From the given following sol how many can coagulate silicic acid sol? ...

    Text Solution

    |

  8. For the coagulation of 500mL of arsenious sulphide sol, 2mL of 1MNaCl ...

    Text Solution

    |

  9. The coagulation of 100 mL of a colloidal solution of gold is completel...

    Text Solution

    |

  10. The gold number of gelatin is 0.01 . Calculate the amount of gelatin t...

    Text Solution

    |

  11. 526.3mL of 0.5MHCl is shaken with 0.5g of activated charcoal and filte...

    Text Solution

    |

  12. In an experiment, addition of 5.0mL , of 0.006MBaCl(2) to 10.0mL of ar...

    Text Solution

    |

  13. In an adsorption experiment, a graph between log (x/m) versus log P wa...

    Text Solution

    |

  14. In a coagulation experiment, 5mL of As(2)S(3) is mixed with distilled...

    Text Solution

    |

  15. In an adsorption experiment, a graph between log (x/m) versus log P wa...

    Text Solution

    |

  16. The volume of nitrogen gas Vm (at STP) reqired to cover a sample of si...

    Text Solution

    |

  17. Compare the coagulation power of AlCl(3) with that of NaCl . Given tha...

    Text Solution

    |

  18. The coagulation of 100 mL of a colloidal solution of gold is completel...

    Text Solution

    |

  19. 50 mL of standard gold solution needs 0.05 mg of gelatin for its prote...

    Text Solution

    |

  20. The coagulation of 200 mL of a positive colloid took place when 0.73 g...

    Text Solution

    |