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Compare the coagulation power of AlCl(3)...

Compare the coagulation power of `AlCl_(3)` with that of `NaCl` . Given that their coagulation values are `0.093` and `52` respectively?

Text Solution

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As coagulation power is inversely proportional to coagulation value, the ratio of their coagulation power will be
`(Coa gu l)/(Coagu l)=(Coa gu l)/(Coa g u l)`
Thus `AlC_3` has 55 times greater coagulation power than Na
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